Making your own Tesamorelin/Ipamorelin blend, and the science behind it.

[TheEngineer]

ADDING IPAMORELIN INTO A VIAL OF TESAMORELIN FOR THE PERFECT DOSE WITH LESS PINS.

MATH TO GET 1MG TESA + 200mcg IPA PER DOSE​

1. Both peptides form a true solution (not a suspension)

• Tesamorelin and Ipamorelin are acetate salts of peptides. They are highly water-soluble in bacteriostatic water.
• When fully dissolved, the peptide molecules exist as individual molecules (or very small solvated clusters) dispersed among the water molecules.
• This is a true molecular solution, not a suspension of particles that could settle or clump.

2. Brownian motion + diffusion = rapid, complete mixing

• In any liquid at room temperature, molecules are in constant random motion due to thermal energy (this is called Brownian motion).
• This random movement causes molecules to spread from areas of higher concentration to lower concentration until the concentration is identical everywhere in the vial.
• This process is governed by Fick’s laws of diffusion. For peptides of this size in water, the diffusion coefficient is high enough that in a small 2–4 ml vial, complete uniformity is reached in seconds to a few minutes after gentle swirling.
• Swirling creates convection currents that speed up the process even more.

Once this happens, the solution is homogeneous (uniform at the molecular level). There is no longer any “more Ipa in one part of the vial” or “more Tesa in another part.”
3. There is no mechanism for the peptides to separate again

• Both peptides are hydrophilic (water-loving) and have similar chemical properties in bac water.
• There is no chemical reaction, precipitation, crystallization, or hydrophobic effect that would cause one peptide to clump or separate from the other.
• Gravity has no meaningful effect on dissolved molecules at this scale (they do not “settle” like sand in water).
• Entropy (the natural tendency toward disorder) actually favors the mixed state.

As a result, once mixed, the solution stays homogeneous indefinitely (as long as the peptides don’t degrade from heat, light, or time).
4. Therefore, every accurately measured volume contains the exact proportion

• Concentration = total mass of peptide ÷ total volume of solution.
• Because the solution is homogeneous, any subsample (e.g. 0.2 ml) has the exact same concentration as the whole vial.
• This is why pharmacies can make compounded multi-peptide vials that deliver consistent doses from the first draw to the last.

In practice, this is the same principle that allows insulin pens, multi-vitamin IV bags, and thousands of daily peptide users to mix compounds reliably. The science of homogeneity is solid — the solution will be perfectly even.
Exact Math (Step-by-Step)
1. Tesamorelin reconstitution
10 mg Tesamorelin + 1.6 ml bac water
→ Concentration = 10 mg ÷ 1.6 ml = 6.25 mg/ml
2. Ipamorelin reconstitution
10 mg Ipamorelin + 2 ml bac water
→ Concentration = 5 mg/ml
3. Transfer
Add 0.4 ml of the Ipamorelin solution into the Tesamorelin vial.
Amount of Ipamorelin added = 0.4 ml × 5 mg/ml = 2 mg
4. Final mixed vial
o Total Tesamorelin = 10 mg
o Total Ipamorelin = 2 mg
o Total volume = 1.6 ml + 0.4 ml = 2.0 ml
Final concentrations:
o Tesamorelin = 10 mg ÷ 2.0 ml = 5 mg/ml
o Ipamorelin = 2 mg ÷ 2.0 ml = 1 mg/ml
5. Injection draw
Draw 0.2 ml (20 units on a U-100 insulin syringe) from the mixed vial.
What you actually get:
o Tesamorelin = 0.2 ml × 5 mg/ml = 1 mg
o Ipamorelin = 0.2 ml × 1 mg/ml = 0.2 mg = 200 mcg
Perfect 1:1 proportion every single time.

​

 

[TheEngineer]

MATH TO GET 2MG TESA + 200mcg IPA PER DOSE​

The Math (Step-by-Step)
1. Ipamorelin reconstitution (unchanged)
10 mg Ipamorelin + 2 ml bac water
→ Concentration = 5 mg/ml
2. Target final concentrations in the mixed vial
o For 2 mg Tesamorelin in 0.4 ml draw → Tesamorelin concentration must be 5 mg/ml
o For 0.2 mg Ipamorelin in 0.4 ml draw → Ipamorelin concentration must be 0.5 mg/ml
3. Final mixed vial volume
Total Tesamorelin is 10 mg.
At 5 mg/ml concentration, total volume must be:
V = 10 mg ÷ 5 mg/ml = 2.0 ml
4. Amount of Ipamorelin to add
At 0.5 mg/ml concentration in a 2.0 ml vial:
Total Ipamorelin needed = 0.5 mg/ml × 2.0 ml = 1 mg
5. Volume of Ipamorelin solution to transfer
Ipamorelin solution is 5 mg/ml, so:
Transfer volume = 1 mg ÷ 5 mg/ml = 0.2 ml
6. Tesamorelin reconstitution volume
Final volume must be 2.0 ml, and you are adding 0.2 ml of Ipamorelin solution.
Therefore, reconstitute the 10 mg Tesamorelin vial with:
1.8 ml bacteriostatic water
Summary of What You Do

Step​	Action​	Result​
1	Reconstitute 10 mg Tesamorelin with 1.8 ml bac water	5.556 mg/ml Tesa
2	Reconstitute 10 mg Ipamorelin with 2 ml bac water	5 mg/ml Ipa
3	Add 0.2 ml of the Ipamorelin solution into the Tesamorelin vial	Final volume = 2.0 ml
4	Gently swirl until fully dissolved	Homogeneous solution

What You Draw for Injection
Draw 0.4 ml (40 units) from the mixed vial.
You will get exactly:

• Tesamorelin = 0.4 ml × 5 mg/ml = 2 mg
• Ipamorelin = 0.4 ml × 0.5 mg/ml = 0.2 mg = 200 mcg

Perfect every time.

 

[UpDownLeftRightAS*]

This is great. Effectiveness does change with age for Ipa, would you consider increasing that 200 mcg for older age brackets?

 

[JoonyO]

MATH TO GET 2MG TESA + 200mcg IPA PER DOSE​

The Math (Step-by-Step)
1. Ipamorelin reconstitution (unchanged)
10 mg Ipamorelin + 2 ml bac water
→ Concentration = 5 mg/ml
2. Target final concentrations in the mixed vial
o For 2 mg Tesamorelin in 0.4 ml draw → Tesamorelin concentration must be 5 mg/ml
o For 0.2 mg Ipamorelin in 0.4 ml draw → Ipamorelin concentration must be 0.5 mg/ml
3. Final mixed vial volume
Total Tesamorelin is 10 mg.
At 5 mg/ml concentration, total volume must be:
V = 10 mg ÷ 5 mg/ml = 2.0 ml
4. Amount of Ipamorelin to add
At 0.5 mg/ml concentration in a 2.0 ml vial:
Total Ipamorelin needed = 0.5 mg/ml × 2.0 ml = 1 mg
5. Volume of Ipamorelin solution to transfer
Ipamorelin solution is 5 mg/ml, so:
Transfer volume = 1 mg ÷ 5 mg/ml = 0.2 ml
6. Tesamorelin reconstitution volume
Final volume must be 2.0 ml, and you are adding 0.2 ml of Ipamorelin solution.
Therefore, reconstitute the 10 mg Tesamorelin vial with:
1.8 ml bacteriostatic water
Summary of What You Do

Step​	Action​	Result​
1	Reconstitute 10 mg Tesamorelin with 1.8 ml bac water	5.556 mg/ml Tesa
2	Reconstitute 10 mg Ipamorelin with 2 ml bac water	5 mg/ml Ipa
3	Add 0.2 ml of the Ipamorelin solution into the Tesamorelin vial	Final volume = 2.0 ml
4	Gently swirl until fully dissolved	Homogeneous solution

What You Draw for Injection
Draw 0.4 ml (40 units) from the mixed vial.
You will get exactly:

• Tesamorelin = 0.4 ml × 5 mg/ml = 2 mg
• Ipamorelin = 0.4 ml × 0.5 mg/ml = 0.2 mg = 200 mcg

Perfect every time.

Question.
There's been a lot of chatter about NOT REFRIGERATING Tesa recently ( and using the reconned within a week ) so I have to wonder about storage of the combo.
Thoughts?
👍

 

[Calm Logic]

There's been a lot of chatter about NOT REFRIGERATING Tesa recently ( and using the reconned within a week )

We already talked about that BS, as in bro science:

https://glp1forum.com/threads/reconstituted-tesamorelin-storage.11074/post-120036

The Rx version of tesa is desiged differently. We have to worry about sterility since there is nothing special in the Chinese powder to preserve once reconned.

 

[JoonyO]

Thanks for the link to the discussion.